Solve the equation using the quadratic formula. 4x2 – 12x +33 = 0

Mathematics

1 answer:

mixer [17]2 years ago

8 0

Answer:

4x2–12x+33=0

Resta 4x

en los dos lados. Cualquier valor restado de cero da como resultado su valor negativo.

−12x+33=−4x

Resta 33 en los dos lados.

−12x=−4x

−33

Divide los dos lados por −12.

−12

−12x

−12

−4x

−33

Al dividir por −12, se deshace la multiplicación por −12.

−12

−4x

−33

Divide −4x

−33 por −12.

Resolver para x_2

=3x−

Step-by-step explanation:

You might be interested in

Marcelis takes a taxi to the airport. The taxi charges $2 per mile and an initial fee of

Marizza181 [45]

Answer:

13 miles

Step-by-step explanation:

27.50- 1.50(fee)=26.00 26/2(2$per mile)=13 miles

4 0

2 years ago

The resting heart rate of an adult is usually about 60 beats per minute. Use your completed table to find approximately how many

Dvinal [7]

60x=1,000,000
----- ---------------
60 60
X=16,666 2/3 or
X=16,666.6667 it would take approximately 16,667 minutes for the average resting heart to beat 1,000,000 times.

3 0

2 years ago

. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i

KIM [24]

Answer:

Error of Andrew: Made incorrect factors from the roots

Step-by-step explanation:

Roots of the polynomial are: 3, 2 + 2i, 2 - 2i. According to the factor theorem, if a is a root of the polynomial P(x), then (x - a) is a factor of P(x). According to this definition:

(x - 3) , (x - (2 + 2i)) , (x - (2 - 2i)) are factors of the required polynomial.

Simplifying the brackets, we get:

(x - 3), (x - 2 - 2i), (x - 2 + 2i) are factors of the required polynomial.

This is the step where Andrew made the error. The factors will always be of the form (x - a) , not (x + a). Andrew wrote the complex factors in form of (x + a) which resulted in the wrong answer.

So, the polynomial would be:

$(x - 3)(x - 2 - 2i)(x - 2+2i)=0\\\\ (x-3)(x^{2}-2x+2xi-2x+4-4i-2xi+4i-4i^{2})=0\\\\ (x-3)(x^{2}-4x+4+4)=0\\\\ (x-3)(x^{2}-4x+8)=0\\\\ x^{3}-4x^{2}+8x-3x^{2}+12x-24=0\\\\ x^{3}-7x^{2}+20x-24=0$