Option A. is correct for the given condition.
Lets solve it through steps of range and functions,
First of all, Solve the equation:
(1)
(2)
So these would be the ranges of X in between 5 and -5.
Hence option A. is correct.
Learn more about range and functions on:
https://brainly.ph/question/10400053
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Answer:
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
μ of the time a group of boys run the mile in its secondary- school fitness test = 440 seconds
σ of the time a group of boys run the mile in its secondary- school fitness test = 40 seconds
2. Find the probability that a randomly selected boy in school can run the mile in less than 348 seconds.
Let's find out the z-score, this way:
z-score = (348 - 440)/40
z-score = -92/40 = -2.3
Now let's find out the probability of z-score = -2.3, using the table:
p (-2.3) = 0.0107
p (-2.3) = 0.0107 * 100
p (-2.3) = 1.1% (rounding to the next tenth)
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Answer:
a) P(2)=0.270
b) P(X>3)=0.605
c) P=0.410
Step-by-step explanation:
We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:
a) In this case:
Therefore, the probability is P(2)=0.270.
b) In this case:
Therefore, the probability is P(X>3)=0.605.
c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.
In this case:
Therefore, the probability is P=0.410.
I think u r sopost to multiply 10 times 2