Answer:
Step-by-step explanation:
x^3-2y^2-3x^3+z^4
(3)^3-2(5)^3+(-3)^4
-142
Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be
4x + 2y = 20
There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.
When x=0,
4(0) + 2y = 20
y = 10
When x=1,
4(1) + 2y = 20
y = 8
When x=2,
4(2) + 2y = 20
y = 6
When x=3,
4(3) + 2y= 20
y = 4
When x = 4,
4(4) + 2y = 20
y = 2
When x = 5,
4(5) + 2y = 20
y = 0
When x = 6,
4(6) + 2y = 20
y = -2
A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:
Number of adult tickets Number of children tickets
0 10
1 8
2 6
3 4
4 2
5 0
If the annual rate in 10 years has the same quadralaterical value the answer would be 47.9 but we can make sure our answer is correct
what we know:
The cost changed in 10 years to 23.95
if the cost changed another 10 years it would be another 23.95, 23.95+23.95=47.9 Which is our answer pls mark brainliest
P(y)=4/15
P(r)= 3/14
(I’m assuming this is without replacement since you are the starburst, so there is one less of the total.)
Answer:
Look at the explanation.
Step-by-step explanation:
Start y=-2x-3 at the Y -3 and X 0, then go up two and to the right one, like a staircase. For y=-x+3 start on Y 3 and X 0 and go down 1 x and 1 y like a downstair staircase with 1 unit down.
