Answer:
Gravitational
Tension
Normal
Friction.
Explanation:
The forces acting on the sled are:
Tension: the tension from the rope, this is the force that "moves" the sled.
Friction: kinetic friction between the sled and the ground as the sled moves.
There are another two forces that also act on the sled, but that "has no effect"
Gravitational force: This force pulls the sled down, against the floor.
Normal force: This force "opposes" to the gravitational one, so they cancel each other.
These two forces cancel each other, so they have no direct impact on the movement of the sled. BUT, the friction force depends on the weight of the moving object, and the weight of the moving object depends on the gravitational force, so we need gravitational force in order to have friction force.
Then we can conclude that the forces acting on the sled are:
Gravitational
Tension
Normal
Friction.
It depends on which side. Opposites attract, so north and south would attract to each other and collide, while north and north or south and south would go away from eachother.
Speed is the sum of distance divided by time (speed = distance / time). So if you were to decrease the distance traveled over the same period of time, this will decrease the speed. If either distance or time is increased or decreased, the speed will do the same.
Answer:
Imp_{1-2}=5000[kg*m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of momentum, which is defined as the product of mass by Velocity.
It must be defined that the impulse after the force is applied is equal to the momentum before the impulse applied on the body.
ΣPbefore = ΣPafter
P = momentum = m*v [kg*m/s]
In this way, we will construct the following equation.
where:
m₁ = mass of the object = 200 [kg]
v₁ = velocity of the object before the impulse = 15 [m/s]
v₂ = velocity of the object after the impulse = 40 [m/s]
Now replacing: