All categories

2 years ago

Consider the expression 5a + (-4b), where bis a negative number and a

Mathematics

1 answer:

Leona [35]2 years ago

6 0

The sum is negative.

You might be interested in

Y-3=4(x+2) solution for x and y please

kolbaska11 [484]

The solution for X= 0 and for y= 4x+11

6 0

2 years ago

Read 2 more answers

The weight of an object on the moon varies directly as its weight on Earth. With all of his gear on, Neil Armstrong weighed 360

babymother [125]

amistre64 Medals 0
e = k.m
360 = k.60
k = 360/60 = 36/6 = 6
108 = 6.m
108/6 = m = 18

8 0

2 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim (x, y) → (0, 0) x4 − 34y2 x2 + 17y2

HACTEHA [7]

Answer:

Step-by-step explanation:

Given the limit of the function $\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}$ , to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

$= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)$

Step 2: Substitute y = mx int o the function and simplify

$= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\$

$= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\$

<em>Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE</em>

4 0

2 years ago

Please help <br> I need this today :(

yuradex [85]

Step-by-step explanation:

Use COS method (Cos Angle = adjacent/hypotenuse)

given adjacent = 14 ft

hypotenuse = 67 ft

$\cos(x) = \frac{adjacent}{hypotenuse} \\ \cos(x) = \frac{14}{67} \\ x = {cos}^{ - 1} ( \frac{14}{67} ) \\ = 78 \: deg(nearest \: degree)$

5 0

2 years ago

3x (x + 6) = 0 Solve:

irakobra [83]

Answer:

-18

Step-by-step explanation:

Google tbh

5 0

2 years ago