-- Take a straight ruler.
-- Lay it down with the 'zero' mark at the start point.
-- Rotate it around the start point until the end point is also touching the edge of the ruler.
-- From the marks on the ruler, read the straight-line distance from the start point to the end point.
-- Without moving the ruler, observe and write down the DIRECTION from the start point to the end point.
-- The Displacement is the straight-line distance and direction from the start point to the end point.
Answer:
a) 6.4 kJ
b) 43.4 kJ
Explanation:
a)
= Heat absorbed = 37 kJ
= Coefficient of performance = 5.8
= Work done
Heat absorbed is given as
=
37 = (5.8)
= 6.4 kJ
b)
= work per cycle required
= +
= 37 + 6.4
= 43.4 kJ
<span>The law of conservation of matter and energy relates to the cycles in nature, and by that it is also applied to rocks and other materials. All of the rock in the Earth is recycled and accounted for during the rock cycle. Rocks experience physical change, the composition of the material stays the same, it may just change how it looks and chemical changes occur (the suubstance undergoes a chemical reaction that changes the actual makeup of the substance).</span>
Answer:
(1) The orbits are ellipses, with focal points ƒ1 and ƒ2 for the first planet and ƒ1 and ƒ3 for the second planet. The Sun is placed in focal point ƒ1.
(2) The two shaded sectors A1 and A2 have the same surface area and the time for planet 1 to cover segment A1 is equal to the time to cover segment A2.
(3) The total orbit times for planet 1 and planet 2 have a ratio a13/2 : a23/2
At surface,
v = kq/r
And potential energy of an electron is given by,
PE = -ev = -ekq/r
At escape velocity,
PE + KE = 0.
Therefore,
1/2mv^2 - ekq/r =0
1/2mv^2 = ekq/r
v = Sqrt [2ekq/mr], where v = escape velocity, e = 1.6*10^-19 C, k = 8.99*10^9 Nm^2/C^2, m = 9.11*10^-31 kg, r = 1.1*10^-2 m, q = 8*10^-9 C
Substituting;
v = Sqrt [(2*1.6*19^-19*8.99*10^9*8*10^-9)/(9.11*10^-31*1.1*10^-2)] = 47949357.23 m/s ≈ 4.795 *10^7 m/s
