Step-by-step explanation: The area of a triangle is 1/2 (Bh); 1*1= 1 (1/2)= 1/2 units². For the other shape, I cut it into a square and another triangle. The square area is length times width; 1*1= 1 units². The final triangle is 3*1= 3*1/2= 1.5 units². Lastly you add all the areas together: 1.5+0.5+1= 3 units²

7 0

1 year ago

A particle is moving along the curve y= 4sqrt(5x+11) . As the particle passes through the point (5,24) , its -coordinate increas

kupik [55]

The rate of change of the distance from the particle to the origin at this instant is 3 units per second.

<h3>What is the rate of change?</h3>

The instantaneous rate of change is the rate of change at a particular instant.

A particle is moving along the curve

$y= 4\sqrt{5x+11} .$

The rate of change of y is given as:

dy / dx = 2

by differentiating both sides,

$\dfrac{dy}{dx} = 4\dfrac{1}{2\sqrt{5x+11} } 5\dfrac{dx}{dt} \\\\\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\$

From the question, we have:

(x, y) = (5,24)

Substitute 5 for x and dy / dx = 2

$\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\\\5= \dfrac{10}{\sqrt{5(5)+11} }\dfrac{dx}{dt}\\\\\\\sqrt{5(5)+11} = 2\dfrac{dx}{dt}\\\\\\\dfrac{dx}{dt} = 6/ 2 = 3$

Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.

Read more about rates of change at:

brainly.com/question/13103052

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8 0

1 year ago

a) Saturn is 9.1 * 10^8 miles from the sun and earth is 9.3 * 10^7 miles from the sun. By what distance is one planet closer to

Sonbull [250]

Answer:

8.17 * 10^8

Step-by-step explanation:

Saturn is 9.1 * 10^8 miles from the sun, and earth is 9.3 * 10^7 miles from the sun. From this, we can see that Saturn is much farther from the sun than the earth.

To find the distance of one planet closer to the sun than the other planet, we can subtract 9.3 * 10^7 from 9.1 * 10^8.

Original expression: 9.1 * 10^8 - 9.3 * 10^7

Convert both sides to 10^7: 91 * 10^7 - 9.3 * 10^7

Subtract: 81.7 * 10^7

Simplify: 8.17 * 10^8

Let me know if this helps!

6 0

2 years ago