Answer:
That information is better presented and analyzed in a table.
This table shows you all the information and the answers:
Substance melting point boiling point room temperature conclusion
°C °C °C (state)
A 0 100 25 liquid
B 50 200 25 solid
C -150 10 25 gas
Explanation:
1) Substance A at 25° is above the melting point and below the boiling point, then it is liquid (just like water)
2) Substance B at 25°C is below the melting point, so it is solid.
3) Substance C at 25°C is above the boiling point, so it is gas.
Much of biological studies are actually chemistry because of chemical changes that occur within organisms. Similarly, large parts of chemistry are governed by physics.
K5O2
convert grams to moles, divide both by the smallest mole mass, multiply that until hole.
30.5 g K ÷ 39.10 = .78 mol
6.24 g O ÷ 16 = .39 mol
.78 mol ÷ .39 mol = 2.5
.39 mol ÷ .39 mol = 1
2.5 x 2 = 5
1 x 2 = 2
K5O2
if your serious about this question then it is 5
168.96 g of carbon dioxide (CO₂)
Explanation:
The chemical reaction representing the combustion of acetylene:
2 C₂H₂ (g) + 5 O₂ (g)→ 4 CO₂ (g) + 2 H₂O (g)
number of moles = mass / molecular weight
number of moles of acetylene (C₂H₂) = 50 / 26 = 1.92 moles
Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:
if 2 moles of acetylene (C₂H₂) produces 4 moles of carbon dioxide (CO₂)
then 1.92 moles of acetylene (C₂H₂) produces X moles of carbon dioxide (CO₂)
X = (1.92 × 4) / 2 = 3.84 moles of carbon dioxide (CO₂)
mass = number of moles × molecular weight
mass of carbon dioxide (CO₂) = 3.84 × 44 = 168.96 g
Learn more about:
combustion of hydrocarbons
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