1. (x+y)2 when x= −3, y= 14

Mathematics

1 answer:

Vikentia [17]2 years ago

6 0

Answer:

$(x+y)2\\ (-3+14)2\\ -6+28\\ 22\\ \\$

$-2x+17\\ -2(8)+17\\ -16+17\\ 1$

$10-3m\\ 10-3(5)\\ 10-15\\ -5$

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Both rooms share a common side whose dimension is unknown. Call it x.

Then, the area of both squares have x as common factor.

So, x is the greatest common factor of 104 and 130.

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Just find the prime factors and choose the common factors raised to the lowest exponent.

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Answer: 26

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