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2 years ago

Calculate the mass in carbon units respectively: 7K , 12Si , 15P

Chemistry

1 answer:

Snezhnost [94]2 years ago

5 0

Answer:

cacqcqcqcacacacacaccacqcacacacqcq

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What is the expected outcome of adding a catalyst to a chemical reaction?

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1. A 250g chunk of metal is heated with 400 joules of energy and the temperature goes from 20 °C to 25°C. What is its specific h

Paha777 [63]

The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.

<u>Given the following data:</u>

Mass of metal = 250g

Quantity of energy = 400 Joules

Initial temperature = 20°C

Final temperature = 20°C

To determine the specific heat capacity of this chunk of metal:

<h3>The formula for quantity of heat.</h3>

Mathematically, quantity of heat is given by the formula;

$Q = mc\theta$

<u>Where:</u>

Q represents the quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity.

∅ represents the change in temperature.

Making c the subject of formula, we have:

$c = \frac{Q}{m\theta}$

Substituting the given parameters into the formula, we have;

$c = \frac{400}{250 \times (25-20)}\\\\c = \frac{400}{250 \times 5}\\\\c = \frac{400}{1250 }$

Specific heat, c = 0.32 J/g°C.

Read more on specific heat here: brainly.com/question/2834175

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1 year ago

Do Atoms of one element change into Atoms of another element during chemical reactions

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2 years ago

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How do sound waves travel? PLEASE HELP IF YOU WANT BRAINLEIST AND ME TO LIKE URE COMMENT!!

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2 years ago

The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres

Dima020 [189]

Answer:

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as $K_{p}$

$2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)$

Partial pressures at equilibrium:

$p^o_{H_2O}=0.070 atm$

$p^o_{H_2}=0.0035 atm$

$p^o_{O_2}=0.0025 atm$

The equilibrium constant in terms of pressures is given as:

$K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}$

$K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}$

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

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2 years ago