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2 years ago

Planets A and B have the same size, but planet A is half the mass of planet B.

Physics

1 answer:

strojnjashka [21]2 years ago

4 0

C is correct as a planet with less mass means less gravity.

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What is the mass of an object moved with a force of 540 N at an acceleration of 7.74 m/s2?

Nataly_w [17]

okay u need to use the equation m=Fnet/a. Fnet=540N a=7.74m/s^2 m=540N/7.74m/s^2=69.77kg

5 0

2 years ago

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A student measures the speed of sound by echo destiny classes hands and then measures the time to hear the echo his distance to

777dan777 [17]

Explanation:

∆x=300 m×2

∆t=1.5 s

v=∆x/∆t → v=2×300/1.5 = 400 m/s

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2 years ago

When light of wavelength 240 nm falls on a cobalt surface, electrons having a maximum kinetic energy of 0.17 eV are emitted. Fin

dusya [7]

Answer:

(a) 5.04 eV (B) 248.14 nm (c) $1.21\times 10^{15}Hz$

Explanation:

We have given Wavelength of the light \lambda = 240 nm

According to plank's rule ,energy of light

$E = h\nu = \frac{hc}{}\lambda$

$E = h\nu = \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{ 240\times 10^{-9} m\times 1.6\times 10^{-19}J/eV}= 5.21 eV$

Maximum KE of emitted electron i= 0.17 eV

Part( A) Using Einstien's equation

$E = KE_{max}+\Phi _{0}$ , here $\Phi _0$ is work function.

$\Phi _{0}=E - KE_{max}$ = 5.21 eV-0.17 eV = 5.04 eV

Part( B) We have to find cutoff wavelength

$\Phi _{0} = \frac{hc}{\lambda_{cuttoff}}$

$\lambda_{cuttoff}= \frac{hc}{\Phi _{0} }$

$\lambda_{cuttoff}= \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{5.04 eV\times 1.6\times 10^{-19}J/eV }=248.14 nm$

Part (C) In this part we have to find the cutoff frequency

$\nu = \frac{c}{\lambda_{cuttoff}}= \frac{3\times 10^{8}m/s}{248.14 \times 10^{-19} m }= 1.21\times 10^{15} Hz$

5 0

2 years ago

A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. It begins the trip traveling 120 m/s and decelerates to

podryga [215]

I believe it is -1.11 m/s^2. I will let you know if its correct

7 0

2 years ago

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After a magnetic field is applied, how many energy levels would you expect for then=3,ℓ=2 state, including electron spin?

zloy xaker [14]

Answer:

The energy level is 5.

Explanation:

Given that,

n = 3

l = 2

We know that,

l shows the number of sub-shells and define the number of angular nodes.

n shows the number of electron shell.

$m_{l}$ is a quantum number. It is define the number of energy level in a sub-shells .

$m_{s}$ is define the spin of the electron.

So, The quantum number is

$m_{l}=-2,-1,0,1,2$

$m_{s}$ is $+\dfrac{1}{2}$ and $-\dfrac{1}{2}$ for every energy level.

The energy level is 5.

Hence, The energy level is 5.

7 0

2 years ago