It would be a a 6 by 5 inch rectangle, since the height is 6in and the width is 5in. Those are what would make up the cross section.
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
Lets say that the two unknown integers are
and
.
We know the following things about
and
:
And, we want to find
.
To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:
So, given what we know about the unknown integers, the previous can be written as:
We can easily solve for
:
The answer is 168.
Another approach to solve the problem is, from the two starting equations, compute the values of
and
, which are 12 and 14, and directly compute their product; however, the approach described is more elegant.
Answer:
a
Step-by-step explanation:
Hey there, Damonealy!
The correct answer should be D since you are talking about multiple amount of data. As you can see, question number 1-3 are talking about the age of a single person but question D is talking about the ages of multiple students which can be used in a statistic.
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