Answer:
- Total number of cars having no defection
- Total number of cars out of 560 will have defects =
Step-by-step explanation:
As
- A car factory checks 320 cars, and
Total number of cars = 560
The number of cars defected out of the cars that have
been checked = 
The equation of the scenario will be:
![\left[560\:\times \:308\right]\:\div \:320](https://tex.z-dn.net/?f=%5Cleft%5B560%5C%3A%5Ctimes%20%5C%3A308%5Cright%5D%5C%3A%5Cdiv%20%5C%3A320)
⇒ 
so
- Total number of cars having no defection
- Total number of cars out of 560 will have defects =
Answer:
a=6, b=-12, and c=0
Step-by-step explanation:
The standard format for the quadratic formula is ax^2+bx+c (=0).
If we rearrange the numbers given to look like this formula, we will find the values of a, b, and c.
6x^2=12x We can move over the 12x to the other side.
6x^2-12x=0 There is no visible value of c, but since there is no term without a variable, c=0
6x^2-12x+0=0
So a=6, b=-12, and c=0
43 and 5/6 because 12 and 1/4*2 is 24 and 1/2 then 9 and 2/3*2 is 19 and 1/3 and when you add that you get 43 and 5/6
Answer:
d
Step-by-step explanation:
X1 = -12 , x2 = 8 ... is the answer
