Answer:
ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.
Step-by-step explanation:
It is given that the triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4.
If a figure is dilated then preimage and image are similar.
If scale factor is between 0 to 1, then preimage is reduction of image.
If scale factor is more that 1, then preimage is enlargement of image.
If scale factor is 1, then preimage is congruent to the image.
We know that
So,
Therefore, the ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.
Answer:
see this img
Step-by-step explanation:
img ☻
Answer:
a= 11, b= 12
Opposite angles of parallelogram are equal.
m<D = m<B
9b-2=106°
9b= 108°
b= 12°
Sum of the adjacent angles of a parallelogram = 180°
m<B+m<C = 180°
106°+7a-3=180°
7a = 180°-106°+3
7a=77°
a= 11°
I would say that it is either <span>B. Multiply the second equation by 4. Then add that result to the first equation or </span><span>D. Add the two equations together </span>