The object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
<h3>What is the distance?</h3>
Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
It is given that:
An object is traveling at a steady speed of 10 1/5 mi/h.
u = 10 1/5 min/h
u = 51/5 min/h
As we know, the speed-distance relationship:
time = distance/speed
distance = 1 4/5 = 9/5
time = (9/5)/(51/5)
time = 9/51 hours
time = (9/51)60
time = 10.58 minutes
Thus, the object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
Learn more about the distance here:
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Length (L): w + 3 ⇒2(w + 3)
width (w): w ⇒ w - 1
Area (A) = L x w
A = (w + 3)(w)
A = w² + 3w
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A + 176 = 2(w + 3)(w - 1)
(w² + 3w) + 176 = 2(w + 3)(w - 1)
w² + 3w + 176 = 2w² + 4w - 6
3w + 176 = w² + 4w - 6
176 = w² + w - 6
0 = w² + w - 182
0 = (w - 13) (w + 14)
0 = w - 13 0 = w + 14
w = 13 w = -14
Since width cannot be negative, disregard -14
w = 13
Length (L): w + 3 = (13) + 3 = 16
Answer: width = 13 in, length = 16 in
Answer:
Step-by-step explanation:
hello : look this solution
We have, 32% × x = 3000
or, 32100 × x = 3000
Multiplying both sides by 100 and dividing both sides by 32,
we have x = 3000 × 10032
x = 9375
If you are using a calculator, simply enter 3000×100÷32, which will give you the answer.
Answer - 100,000
