A taxi service offers a ride with an $5 sub charge and charges 0.50 per mile

Graph the points a (-5,0) b (-4,3) and c (0,-4) on the same coordinate plane

Delicious77 [7]

The marks are by 1 so just count

5 0

2 years ago

I need help ASAP!!!Please explain you answer

just olya [345]

Answer:

Step-by-step explanation:

The body of the Cylinder.

Formula

Area of the body = circumference * length

circumference = 2*pi * r

r = 6 m

Circumference = 2 * 3.14 * 6

Circumference = 12 * pi

Area of body = 12*pi * length

area of body = 12*9 * pi

Area of body = 108* pi

Two ends

The diagram is not complete enough to know whether or not there are 2 ends or one. I'll assume 2.

Area = 2 * pi r^2 For both

Area = 2 * pi * 6^2

Area = 72 pi

Total Area

Total area = 72 pi +108 pi

Total area = 180 pi

Total Area = 180 * 3.14

Total Area = 565.2

5 0

2 years ago

A boat’s velocity, measured in meters per second, is described by vector b⇀=⟨3,4⟩. In two or more complete sentences explain how

Sedbober [7]

Answer: Velocity is a vector, so it has a magnitude and direction.

Speed is its magnitude, which is obtained from

|〈-3, 4〉 m/s| = √((-3 m/s)² + (4 m/s)²) = √(25 m²/s²) = 5 m/s

Its direction is an angle θ made with the positive horizontal axis, satisfying

tan(θ) = (4 m/s) / (-3 m/s) = -4/3 → θ = arctan(-4/3) + 180°n

where n is any integer. Now you have to consider that the x coordinate is negative and the y coordinate is positive, so 〈-3, 4〉 points into the second quadrant, and we get an angle there for n = 1 of about

θ ≈ 126.87°

Alternatively, you can use the vector 〈1, 0〉 in place of the axis, then compute the angle by relating it to the dot product, so θ is such that

〈-3, 4〉 • 〈1, 0〉 = |〈-3, 4〉| |〈1, 0〉| cos(θ)

(-3)•1 + 4•0 = √((-3)² + 4²) • √(1² + 0²) cos(θ)

-3/5 = cos(θ) → θ = arccos(-3/5) + 360°n

where again, n is any integer, and we get the same solution θ ≈ 126.87° in the second quadrant when n = 0.

Step-by-step explanation:

5 0

1 year ago

What is the integer for 2°f above zero

Illusion [34]

2 F above zero would be 2. Unless it says in Celsius or Kelvin.
Integer is just a fancy way of saying whole number

5 0

2 years ago

The line l is tangent to the circle with equation x^2 + y^2=10 at the point P.

babunello [35]

Given:

The equation of a circle is

$x^2+y^2=10$

A tangent line l to the circle touches the circle at point P(1,3).

To find:

The equation of the line l.

Solution:

Slope formula: If a line passes through two points, then the slope of the line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Endpoints of the radius are O(0,0) and P(1,3). So, the slope of radius is

$m_1=\dfrac{3-0}{1-0}$

$m_1=\dfrac{3}{1}$

$m=3$

We know that the radius of a circle is always perpendicular to the tangent at the point of tangency.

Product of slopes of two perpendicular lines is always -1.

Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.

$m\times m_1=-1$

$m\times 3=-1$

$m=-\dfrac{1}{3}$

The slope of line l is $-\dfrac{1}{3}$ and it passs through the point P(1,3). So, the equation of line l is

$y-y_1=m(x-x_1)$

$y-3=-\dfrac{1}{3}(x-1)$

$y-3=-\dfrac{1}{3}(x)+\dfrac{1}{3}$

Adding 3 on both sides, we get

$y=-\dfrac{1}{3}x+\dfrac{1}{3}+3$

$y=-\dfrac{1}{3}x+\dfrac{1+9}{3}$

$y=-\dfrac{1}{3}x+\dfrac{10}{3}$

Therefore, the equation of line l is $y=-\dfrac{1}{3}x+\dfrac{10}{3}$ .

4 0

1 year ago