Answer:
<em>1.228 x </em><em> mm </em>
<em></em>
Explanation:
diameter of aluminium bar D = 40 mm
diameter of hole d = 30 mm
compressive Load F = 180 kN = 180 x N
modulus of elasticity E = 85 GN/m^2 = 85 x Pa
length of bar L = 600 mm
length of hole = 100 mm
true length of bar = 600 - 100 = 500 mm
area of the bar A = =
= 1256.8 mm^2
area of hole a = =
= 549.85 mm^2
Total contraction of the bar =
total contraction =
==> = <em>1.228 x </em>
<em> mm </em>
The density of the fluid is 776.3
<u>Explanation:</u>
Buoyant force is the upward pushing force whenever an object is trying to get immersed in fluid. So this is the force given by the fluid on the object which is trying to get immersed. The buoyant force is found to be directly proportional to the product of density of the object, volume of the object. And here the acceleration due to gravity will be acting as proportionality constant.
As, buoyant force is given as 671 N and volume is 0.0882 and acceleration is known as 9.8 m/
. Then density is
Thus,
Density is 776.3 kg .
Solution :
Given data is :
Density of the milk in the tank,
Length of the tank, x = 9 m
Height of the tank, z = 3 m
Acceleration of the tank,
Therefore, the pressure difference between the two points is given by :
Since the tank is completely filled with milk, the vertical acceleration is
Therefore substituting, we get
Therefore the maximum pressure difference in the tank is Δp = 47.87 kPa and is located at the bottom of the tank.