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2 years ago

The difference between six times a number and 7 is equal to five times the sum of the number and 4. Find the number.

1 answer:

8 0

The difference (subtraction) of 6 times a number (x represents number) and 7. This gives us 6x-7. That is equal to five times (multiplication) the sum (addition) of the number, x, and 4. This gives you = 5(x+4) and combined gives us B, 6x-7=5(x+4).

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Item 5<br> What is the interquartile range of this data set?

fomenos

Answer:

its 13.0

Step-by-step explanation:

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1 year ago

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$

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2 years ago

8.5 x 10-2 what is the scientific notation of this?

Butoxors [25]

Answer: 0.085

Step-by-step explanation:

Assuming you mean 10 to the power of -2, shift the decimal point two places to the left.

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2 years ago

What is the perimeter of this book?

Lana71 [14]

C. 32in. >> 10+10+6+6=32.

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2 years ago

20. What is the transformation?:

schepotkina [342]

Answer:

Reflection

Step-by-step explanation:

A rotation would be to rotate a figure around the origin

A reflection would be to reflect the figure around one of the axes.

A translation would be to move a figure a certain amount of units.

Since A and A' are 2 units away from the y-axis, and C, B, B', and C' are all one unit away from the y-axis, this could not be a translation because the position of A'B'C' is not the same position of ABC.

It could not be a rotation around the origin or any point because it would result the figure in either Quadrant 2 or 3, and in the one occasion it would be in Quadrant 1, the figure cannot be in that position.

This reveals only one option, that which is a reflection. A reflection about the x-axis would not make sense, since it would result in Quadrant 3, so a reflection around the y-axis would make the most sense.

The data we have above also accounts for a reflection, since all points are a certain distant away from the y-axis.

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2 years ago

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