Answer:
I'm confused. Is there more to the question?
Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
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You're looking for a solution of the form
where
and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:
Then
The general solution to the ODE is
which simplifies somewhat to
Answer:
(Hope this helps can I pls have brainlist (crown) ☺️)
Step-by-step explanation:
In pic
Answer:
7/30
Step-by-step explanation:
We are given that Seven-ninths (7/9) of the pencils in a box are yellow and three-tenths (3/10) of the yellow pencils are sharpened.
To find the fraction that represents sharpened yellow pencils, we find the product of the the fraction of yellow pencils and the fraction of yellow pencils that are sharpened.
That is:
=> (7 / 9) * (3 / 10)
=(7 * 3) / (9 * 10)
= 21 / 90
= 7 / 30
7/30 represents the fraction of sharpened yellow pencils.
Answer:
15
Step-by-step explanation:
By the diagram, you can see the sum of segment AB and segment BC is segment AC. Adding the given expressions for AB and B is . Simplifying the equation , gives . Substituting in the equation for segment AC gives 15.