Given a right triangle with hypothenus of measure 34, the side opposite the angle θ of measure 30, and the side adjacent the angle theta of measure 16.

$\sin\theta= \frac{opposite}{hypothenuse} = \frac{30}{34} = \frac{15}{17} \\ \\ \Rightarrow \theta=\sin^{-1}\left( \frac{15}{17} \right) \\ \\ \\ \cos\theta= \frac{adjacent}{hypothenuse} = \frac{16}{34} = \frac{8}{17} \\ \\ \Rightarrow \theta=\cos^{-1}\left( \frac{8}{17} \right) \\ \\ \\ \tan\theta= \frac{opposite}{adjacent} = \frac{30}{16} = \frac{15}{8} \\ \\ \Rightarrow \theta=\cos^{-1}\left( \frac{15}{8} \right)$

3 0

2 years ago

A company makes bicycles in two sizes. The first bicycle size weighs 18.5 pounds. The second bicycle sizes weighs 1/14 as much a

QveST [7]

The second bicycle would weigh 1.32142857143 pounds or rounded to 1.32.
You would find this by multiply 18.5 by 1/14

7 0

2 years ago

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Can someone please help me!!! I need help, no links !!!

Sholpan [36]

Give me a few and I will

4 0

2 years ago