Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 2x - 13
a = 1 b = -2 c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74
Answer:
X=-6
Step-by-step explanation:
4(1−x)+3x=−2(x+1)
(4)(1)+(4)(−x)+3x=(−2)(x)+(−2)(1)(Distribute)
4+−4x+3x=−2x+−2
(−4x+3x)+(4)=−2x−2(Combine Like Terms)
−x+4=−2x−2
−x+4=−2x−2
Step 2: Add 2x to both sides.
−x+4+2x=−2x−2+2x
x+4=−2
Step 3: Subtract 4 from both sides.
x+4−4=−2−4
x=−6
Answer:
x=−6
Answer:
I would help you and say the answer but..
Step-by-step explanation:
I dont know what it is :c
Answer: Ordinal measurement scale
Step-by-step explanation:
In ordinal measurement scale the order of values or variables are very important. Just as in the case above, the rating from 1-3 is according to the order of it's importance.
Thanks
<span>For a rotation of 90o: (x, y) ⇒ (–y, x)
T(3,4) ⇒⇒⇒ T'(-4,3)
W(-2,-1) ⇒⇒⇒ W'(1,-2)
x(-3,3) ⇒⇒⇒ x'(-3,-3)
see the attached figure
</span>
