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2 years ago

How do you feel about the way land is used around you?

Physics

1 answer:

cupoosta [38]2 years ago

5 0

Answer:

I feel that people hurt the land and are destroying. I think they aren't using the land for the right reasons.

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when approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately

Dominik [7]

when approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately 25 feet.

<h3>What impact, if any, would jet fuel and aviation gasoline have on a turbine engine?</h3>

Tetraethyl lead, which is present in gasoline, deposits itself on the turbine blades. Because jet fuel has a higher viscosity than aviation gasoline, it may retain impurities with greater ease.

Once the gasoline charge has been cleared, start the engine manually or with an electric starter while cutting the ignition and using the maximum throttle.

On the final approach, the aeroplane needs to be re-trimmed to account for the altered aerodynamic forces. A substantial nose-down tendency results from the airflow producing less lift on the wings and less downward force on the horizontal stabiliser due to the reduced power and slower velocity.

Learn more about turbine engine refer

brainly.com/question/807662

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7 0

1 year ago

During the first stage of a multistage rocket, a satellite is:

lianna [129]

B. sent through the atmosphere

7 0

2 years ago

All of the following are types of symbiotic relationships except for

nevsk [136]

The answer is D. the way I remember it is they all end with -alism.

3 0

2 years ago

An 88 kg worker stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale reads 900 N. Fi

Aleks [24]

Answer:

The magnitude is "3.8 m/s²", in the upward direction.

Explanation:

The given values are:

Mass,

m = 88 kg

Scale reads,

T = 900 N

As we know,

⇒ $N=mg$

On substituting the given values, we get

⇒ $=88\times 9.8$

⇒ $=862.4 \ N$

Now,

⇒ $T=mg-ma$

On substituting the given values in the above equation, we get

⇒ $900=862.4-9.8 a$

On subtracting "862.4" from both sides, we get

⇒ $900-862.4=862.4-9.8 a-862.4$

⇒ $37.6=-9.8a$

⇒ $a=-\frac{37.6}{9.8}$

⇒ $a=3.8 \ m/s^2$ (upward direction)

8 0

2 years ago

When using a calorimeter, the initial temperature of a metal is 70.4C. The initial temperature of the water is 23.6C. At the end

Sunny_sXe [5.5K]

1) 29.8 C

At the beginning, the metal is at higher temperature (70.4 C) while the water is at lower temperature (23.6 C). When they are put in contact, the metal transfers heat to the water, until they reach thermal equilibrium: at thermal equilibrium the two objects (the metal and the water have same temperature). Therefore, since the temperature of the water at thermal equilibrium is 29.8 C, the final temperature of the metal must be the same (29.8 C).

2) 6.2 C

The temperature change of the water is given by the difference between its final temperature and its initial temperature:

$\Delta T = T_f - T_i$