Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
The second photo is the correct graph.
Answer:
288
Step-by-step explanation:
76+45=121
121+98=219
219+76=295
295-7=288
Answer:
The three-dimensional surface represented by the equation x+y=2 is an inclined plane, as seen in the image.