Answer:
= −
8/5
Step-by-step explanation:
Distribute
3
(
2
+
3
)
=
1
(
+
1
)
6
+
9
=
1
(
+
1
)
Multiply by 1
6
+
9
=
1
(
+
1
)
6
+
9
=
+
1
Subtract
9
9
9
from both sides of the equation
6
+
9
=
+
1
6
+
9
−
9
=
+
1
−
9
Substitute 21 for x.
y = 21 - 4 = 17
Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
x = [-5 ± √(25 - (104) ) ] / ( -4 )
x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
Answer:
6
Step-by-step explanation:
4(6) - 7y = -18
24 - 7y = -18
-7y= -42
y= 6
Answer: Choice B) Angle L = Angle O
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If we know that Angle L is congruent to Angle O, then we can use the AAS (angle angle side) congruence property. We have one pair of angles marked by the square marker (angle J and angle M). So they are congruent angles. We have a pair of congruent sides JK = MN = 3. So we're just missing a pair of angles.
Note: The answer is NOT angle K = angle N because this would mean ASA would be used instead of AAS. The order of the letters is important as it establishes how the sides and angles relate. With ASA, the side is between the angles. With AAS, the side is not between the angles.