Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity
here
speed of first plane is 700 mi/h at 31.3 degree
speed of second plane is 570 mi/h at 134 degree
now the relative velocity is given as
now the distance between them is given as
so the magnitude of the distance is given as
miles
so the distance between them is 2985.6 miles
<span>When an atomic nucleus emits a beta particle, "Atomic number remains same"
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Answer: a) 152 cm
b) 0.725 ms
c) 10°
Explanation:
Given
Frequency of the wave, f = 524 Hz
Speed of the wave, v = 345 m/s
Wavelength of the wave, λ = ?
The relation for wavelength is given by
λ = f/v, on substituting
λ = 524 / 345
λ = 1.52 m or 152 cm
T = 1/v
T = 0.0029 s
T = 2.9 ms.
Note that the phase change is 90°, thus the time required to change the phase by 90° is
t = 2.9 * (90 / 360)
t = 2.9 * 0.25
t = 0.725 ms
The phase difference at a particular instance 4.4 cm apart is
= (4.4 / 152) * 360
= 0.02895 * 360
= 10.422°
a) 152 cm
b) 0.725 ms
c) 10°
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Answer:
4276.98 years
Explanation:
t = age of the sample in numbers of years
T = half life of the carbon-14 isotope = 5730 yrs
λ = decay constant of carbon-14
decay constant is given as
A₀ = activity of Carbon-14 in living plants
A = activity of Carbon-14 after time "t" = (0.596) A₀
Using the equation
t = 4276.98 years
