Which of the following is a unit of volume of solids?

9. Describe two ways in which you can conserve and recycle lab resources.<br> I

Answer:

Using solar energy, hydroelectric energy and wind are major ways of conserving natural resources. Trees and other organic energy sources are traditional sources of renewable energy. Forests can be replanted and hemp and other organic materials such as ethanol can be used to preserve natural resources.

4 0

2 years ago

2Li + H2SO4=Li2SO4 + H2 How many liters of hydrogen gas, H2 at STP can be produced from 3.0 moles of Li? The molar volume of a g

Gemiola [76]

Answer:

volume of $H_2=33.6 litre$

Explanation:

Firstly balance the given chemical equation,

$2Li + H_2SO_4=Li_2SO_4 + H_2$

From the given balance equation it is clearly that,

2 mole of Li gives 1 mole of H2 gas

$2 mole Li$ ⇔ $1 mole H_2$

$1 mole Li$ ⇔ $0.5 mole H_2$

$3 mole Li$ ⇔ $1.5 mole H_2$

hence

3 mole of Li will give 1.5 mole H2 gas

therefore volume of gas produced from 3 mole Li at $STP = 1.5\times22.4 \frac{L}{mol}$

volume of H2=33.6 litre

7 0

2 years ago

A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to

12345 [234]

Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

$\frac{salt}{sugar} = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}$

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

$\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}$

Now we can calculate the amount of sugar in the final solution:

$\frac{salt}{sugar} = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g$

Finally, we calculate the amount of water:

$\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g$

4 0

2 years ago

An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the

san4es73 [151]

Answer:

the ionic radius of the anion $r^- = 312.52 \ pm$

Explanation:

From the diagram shown below :

The anion $Cl^-$ is located at the corners

The cation $Cs^+$ is located at the body center

The Body diagonal length = $\sqrt{3 \ a }$

∴ $2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a} \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a$

Given that :

$\frac{r^+}{r^-} =0.84$ (i.e the ratio of the ionic radius of the cation to the ionic radius of

the anion )

$0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a \\ \\ 1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a$

Also ; a = 664 pm

Then :

$r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm$

Therefore, the ionic radius of the anion $r^- = 312.52 \ pm$

4 0

2 years ago

Why do different elements make different color flames when you burn them?

Dovator [93]

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

7 0

2 years ago