It is a Compound.

Water can't be a mixture because it is chemically bonded and cannot be separated into H2 and O by physical means.

And water cannot be an element, because it is made of atoms of different types [H and Oxygen]

4 0

2 years ago

Calculate the pressure exerted by an book of mass 20kg occupying an area of 2 m square.

kotykmax [81]

The answer is 100 Pa.

The formula for calculating pressure is :

<u>Pressure = Force ÷ Area</u>

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We are given that :

mass = 20 kg
area = 2 m²

We also know that :

<u>Force = mass ×g</u>

<u />

So, force will be :

F = 20 × 10
F = 200 N

Now, we can finally calculate pressure :

P = 200 ÷ 2
P = 100 Pa

8 0

1 year ago

Catalyst

Hoochie [10]

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

<h3>Further explanation</h3>

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

Assume reactants at STP(0 C, 1 atm)

Products at 1000 C (1273 K)and 1 atm

a. mol ratio NO : O2 from equation : 4 : 5, so mo NO :

$\tt \dfrac{4}{5}\times 0.5=0.4$

volume NO at 1273 K and 1 atm

$\tt V=\dfrac{nRT}{P}=\dfrac{0.4\times 0.08206\times 1273}{1}=41.785~L$

b. 15 L NH3 at STP ( 1mol = 22.4 L)

$\tt \dfrac{15}{22.4}=0.67~mol$

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

$\tt \dfrac{6}{4}\times 0.67=1$

mass H2O(MW = 18 g/mol) :

$\tt mass=mol\times MW=1\times 18=18~g$

c. mol NO at 1273 K and 1 atm :

$\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34$

mol ratio of NO : O2 = 4 : 5, so mol O2 :

$\tt \dfrac{5}{4}\times 0.34=0.425$

Volume O2 at STP :

$\tt 0.425\times 22.4=9.52~L$

5 0

2 years ago