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2 years ago

Help please ! Need the answers

Mathematics

1 answer:

son4ous [18]2 years ago

8 0

Answer:

$x=\frac{-5+\sqrt{13}}{6} or x=\frac{-5-\sqrt{13}}{6} (decimal: x=-0.23240 , x=-1.43425)$

Step-by-step explanation:

a = 3, b = 5, c = 1

plug into quadratic formula

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One week John earned three times as much as Alex earned mowing lawns. If they earned $48 altogether,how much did each one earn

Allisa [31]

Answer:Alex earned $12

John earned $36

Step-by-step explanation:

j=3a

a+3a=48

4a=48

a=48/4

a=12

j=36

8 0

2 years ago

What is the product of seven plus two and eight minus two

mr_godi [17]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What the answer now answer only if now answer corry

goblinko [34]

Answer:

Approximately 11.5 units.

Step-by-step explanation:

We need to find the side opposite to ∠W. We are given the two angles ∠W and ∠X. We are also given that Side X is equal to 7. Therefore, we can use the Law of Sines.

Now, like last time, use the Law of Sines:

$\frac{\sin(V)}{v}=\frac{\sin(W)}{w}=\frac{\sin(X)}{x}$

We can ignore the first term. Plug in 144 for ∠W, 21 for ∠X, and 7 for x.

$\frac{\sin(144)}{w}=\frac{\sin(21)}{7}$

Cross multiply:

$7\sin(144)=w\sin(21)\\w=\frac{7\sin(144)}{\sin(21)} \\v\approx11.4812\approx11.5$

6 0

2 years ago

A company invests $32000. after 4 years of growth at the same rate each year, the investment is worth $42692. find the annual gr

Nostrana [21]

Answer:

R = 33.35%

Step-by-step explanation:

that is the solution above

6 0

1 year ago

Need help finding the domain and range

pogonyaev

Here are a few things you'll need to know for this question:

Domain: The list of x-values that are possible on a line.
Range: The list of y-values that are possible on a line.
Interval Notation: Shows the domain/range using the endpoints. Brackets mean that the endpoint is included, parentheses mean the endpoint is excluded. Ex: (2,10]. 2 is excluded, 10 is included.
Closed Circles: The endpoint is included.
Open Circles: The endpoint is excluded.

So firstly, let's look at the domain. We see that there is a closed circle at x = -2 and an open circle at x = 5. Using what we know, the interval notation of the domain is [-2,5).

Next, let's look at the range. We see that there is a closed circle at y = -5 and an open circle at y = 2. Using what we know, the interval notation of the range is [-5,2).

3 0

2 years ago