The electric field at any point in the region between the conductors is proportional to the magnitude Q of charge on each conductor. It follows that:
"The potential difference Vab between the conductors is also proportional to Q"
If we double the magnitude of charge on each conductor, the charge density at each point doubles, the electric field at each point doubles, and the potential difference between conductors doubles; however, the ratio of charge to potential difference does not change. This ratio is called the capacitance C of the capacitor:
Given that:
and
Lastly, the capacitance is given by:
The magnitude of the current in wire 3 is 2.4 A and in a direction pointing in the downward direction.
- The force per unit length between two parallel thin current-carrying and wires at distance ' r ' is given by ....(1) .
- If the current is flowing in both wires in the same direction, and the force between them will be the attractive force and if the current is flowing in opposite direction in wires then the force between them will be the repulsive force.
A schematic of the information provided in the question can be seen in the image attached below.
From the image, force on wire 2 due to wire 1 = force on wire 2 due to wire 3
Using equation (1) , we get
I₃ = 2.4 A and the current is pointing in the downward direction
Learn more about the magnitude and direction of forces here:
brainly.com/question/14879801?referrer=searchResults
#SPJ4
Force = (mass) x (acceleration)
= (0.025 kg) x (5 m/s²)
= 0.125 Newton
the answer should be:
When the buoyant force is equal to the force of gravity
equal and opposite reaction.