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2 years ago

14

18 ÷ 6 × [4 - 3] + 6

2 answers:

Dima020 [189]2 years ago

7 0

Your answer would be 9

18 ÷ 6 × [4 - 3] + 6

18/6 *1+6

3+6

=9

shepuryov [24]2 years ago

6 0

Answer:

9

Step-by-step explanation:

18 ÷ 6 × [1] + 6

18 ÷ 6 + 6

3 + 6

9

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A health club charges an initial fee of $100 to join, plus a fee of $33 per month. Write an algebraic equation. How much will yo

docker41 [41]

#1 answer: y=33x+100

explanation: The initial fee of $100 is your y-intercept.
The 33 is your slope.
You pay $33 a month which is what the x value represents (the month).
So your total equation is y=33x+100

#2 answer: $265

explanation: using the equation y= 33x + 100 you replace the x which is 5.
33(5) + 100. 33 * 5 = $165 but you can’t forget the + 100.
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2 years ago

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dybincka [34]

i) The given function is

$f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}$

The domain is

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$(x-5)\ne0,(x+4)^2\ne 0$

$x\ne5,x\ne -4$

ii) For vertical asymptotes, we simplify the function to get;

$f(x)=\frac{(2x+1)}{(x+4)^2}$

The vertical asymptote occurs at

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$x=-4$

iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

$2x+1=0$

$2x=-1$

$x=-\frac{1}{2}$

iv) To find the y-intercept, we substitute $x=0$ into the reduced fraction.

$f(0)=\frac{(2(0)+1)}{(0+4)^2}$

$f(0)=\frac{(1)}{(4)^2}$

$f(0)=\frac{1}{16}$

v) The horizontal asymptote is given by;

$lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0$

The horizontal asymptote is $y=0$ .

vi) The function has a hole at $x-5=0$ .

Thus at $x=5$ .

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

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2 years ago

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tigry1 [53]

Answer:

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Step-by-step explanation:

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Gennadij [26K]

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Step-by-step explanation:

8 + 12 = 2x

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Alina [70]

Answer:

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2 years ago