The exoskeleton of an arthropod is chitin.
The question is incomplete as it does not have the options which are:
A) n+1; n+1; n-1; n-1
B) n+1; n-1; n; n
C) n+1; n-1; n-1; n-1
D) n+1; n+1; n; n
Answer:
Option-1
Explanation:
The laws of inheritance were concluded from the result of Mendel's experiment which is based on the fact that gametes are formed. Later research suggested that gametes are formed by the process of meiosis which takes place in two phases and recombination is a characteristic of Meiosis.
If during anaphase I of meiosis I, the alleles fails to separate that is nondisjunction takes place at anaphase I, Then the resulting daughter cells will have unequal distribution of chromosomes.
One daughter cell will receive 1 extra copy of the chromosome while another daughter cell will receive 1 less chromosome therefore ploidy level will be n+1 and n-1.
During meiosis II, 2 more daughter cells will be formed with the same ploidy level therefore in last the meiosis will result in 2 (n+1) and 2 (n-1) cell.
Thus, Option-1 is the correct answer.
<span>Endorphin. Endorphin are pepetide hormones secreted by the central nervous system and the pituitary gland. They inhibit the transmission of pain signals; they also produce a feeling of euphoria very similar to the ones produced by other opioids. Its 1 production is usually triggered by various human activities although they are produced in response to pain. Carrying out frequent exercise usually stimulates the release of beta-endorphin in the human brain known as runner's high. This is the probably the reason Mobombi could finish the race pain free.</span>
Answer:
C)
Explanation:
antigen binding to B cell receptors
Answer:
50%
Explanation:
According to the given information, the allele for the red-green colorblindness is inherited in an X linked recessive manner. Let's assume that the allele X^c is responsible for red-green colorblindness. The woman is normal but had a colorblind father (X^cY). Fathers give their X chromosomes to the daughters while their Y chromosome is transmitted to their sons. The sons get their X chromosomes from the mother.
The colorblind father has transmitted the X-linked allele for the red-green colorblindness to his daughter. Therefore, the genotype of the woman is X^cX. The woman would produce two types of eggs: 50 % with X^C and 50% with X. Therefore, 50% of sons of this woman would get X linked allele for the red-green colorblindness and would be affected by the disorder while the rest 50% of her sons will be normal.
