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2 years ago

If I walk 30 m north and turn around and walk 10 m to the south, what is the magnitude

Physics

2 answers:

Karo-lina-s [1.5K]2 years ago

8 0

Answer:

40m

Explanation:

Your total displacement would be 40m! Let me explain.

Going 30m north adds 30 to 0... so your total right now is 30m.

if you turn around and walk 10 m you have to add that 10 to the 30.

so your total displacement is 40m.

miss Akunina [59]2 years ago

5 0

Answer:

Hey

it would be 20 m

If you walk away 30 m then come back 10 you are now 20 m away from your starting point.

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v₂ = 176.24 m/s

Explanation:

given,

angle of projectile = 45°

speed = v₁ = 150 m/s

for second trail

speed = v₂ = ?

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maximum height attained formula,

$H_{max}= \dfrac{v^2 sin^2(\theta)}{g}$

now,

$H_{max}= \dfrac{v_1^2 sin^2(\theta_1)}{g}$

$H_{max}= \dfrac{v_2^2 sin^2(\theta_2)}{g}$

now, equating both the equations

$\dfrac{v_2^2}{v_1^2}=\dfrac{sin^2(\theta_1)}{sin^2(\theta_2)}$

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