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2 years ago

Why is electrostatic force able to act at a distance

1 answer:

mote1985 [20]2 years ago

7 0

In Electrostatics the electrical force between Two charged objects is inversely Related to the distance of separation between the two objects .

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In an exothermic reaction, the energy stored in the reactant is_____ the energy stored in the products.

docker41 [41]

I believe it is B. Greater than

3 0

2 years ago

A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 5.00 m ab

maria [59]

Answer:

W = 0.678 rad/s

Explanation:

Using the conservation of energy:

$E_i =E_f$

Roll up and hill without slipping is the sumatory of two energys, rotational and translational, so:

$\frac{1}{2}IW^2+ \frac{1}{2}mV^2 = mgh$

where I is the moment of inertia, W the angular velocity at the base of the hill, m the mass of the ball, V the velocity at the base of the hill, g the gravity and h the altitude.

First, we will find the moment of inertia as:

I = $\frac{2}{3}mR^2$

where m is the mass and R the radius, so:

I = $\frac{2}{3}(0.426kg)(11.3m)^2$

I = 36.26 Kg*m^2

Then, replacing values on the initial equation, we get:

$\frac{1}{2}(36.26)W^2+ \frac{1}{2}(0.426kg)V^2 = (0.426kg)(9.8)(5m)$

also we know that:

V =WR

so:

$\frac{1}{2}(36.26)W^2+ \frac{1}{2}(0.426kg)W^2R^2 = (0.426kg)(9.8)(5m)$

Finally, solving for W, we get:

$W^2(\frac{1}{2}(36.26)+ \frac{1}{2}(0.426kg)(11.3m)^2) = (0.426kg)(9.8)(5m)$

W = 0.678 rad/s

8 0

2 years ago

Newton's laws of motion work well for ordinary situations on earth. However, these laws of motion do not work for all cases. Und

soldier1979 [14.2K]

I believe the answer is C: For objects at extremely fast speeds.
Hope this helps!

5 0

2 years ago

Read 2 more answers

How long would it take for the turtle to move 650 meters at this speed of 0.05 m/s

Charra [1.4K]

Answer:

t=13000 or t= 1.3x10^4 (ten to the power of four)

Explanation:

d= 650m v=0.05 t=? v= d/t t= d/v 650m/0.05m/s= 13000 if you need to simplify it into scientific notation, move the decimal up, you need to move it up four times, so t= 1.3x10^4s

7 0

2 years ago

A liquid of density 1390 kg/m 3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the

Aloiza [94]

Answer:

The difference of power is

ΔP = 172.767 kPa

Explanation:

ρ = 1390 kg / m³

v = 9.63 m/s

d₁ = 10.1 cm , d₂ = 15.3 cm

Δz = 8.85 m

To find the difference ΔP between the fluid pressure at locations 2 and the fluid pressure at location 1

ΔP = ρ * g * Z + ¹/₂ * ρ * v² * ( 1 - (d₁ / d₂)⁴ )

ΔP = 1390 kg / m³ * 9.8 m/s² * 8.85 m + 0.5 * 1390 kg / m³ *(9.63 m /s)² * (1 - (0.101 m / 0.153 m )⁴ )

ΔP = 172.767 x 10 ³ Pa

ΔP = 172.767 kPa

6 0

2 years ago

Why is electrostatic force able to act at a distance ​

Why is electrostatic force able to act at a distance