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2 years ago

When is the pressure of the man on the ground more – lying position or standing position? Explain.

Physics

1 answer:

Dmitrij [34]2 years ago

3 0

It is without a doubt in standing position!
“I will explain if u ask”
(Please mark brainlest if I helped u a bit)

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HELP!!! When fat comes in contact with sodium hydroxide, it produces soap and glycerin. Determine whether this is a physical cha

dimaraw [331]

Answer:it's a chemical change.physical changes occur without 2 or more reactants,a reaction,and a product

Explanation:

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2 years ago

In the Milky Way Galaxy, where would you expect to find the bulge?

nalin [4]

Answer:

at the sun???

Explanation:

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2 years ago

A mixture can be classified as a solution, suspension, or coiled based on the: A. Number or particles it contains. B. Size of it

gladu [14]

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2 years ago

You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 275 N in the positive x di

Volgvan

Answer:

f = 347.08 N

Explanation:

The frictional force exerted by the floor on the refrigerator is given as follows:

$f = \mu R = \mu W$

where,

f = frictional force = ?

μ = coefficient of static friction = 0.58

W = Weight of refrigerator = mg

m = mass of refrigerator = 61 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$f = \mu mg\\f = (0.58)(61\ kg)(9.81\ m/s^2)\\$

f = 347.08 N

8 0

2 years ago

You work for the city water department and need to pump 3400 liters/minute of water from a tank at ground level into a vented (i

umka21 [38]

Answer:

$P_E=46.2778\ kW$

$v=1.804\ m.s^{-1}$

Explanation:

Given:

flow rate of water, $\dot{V}=3400\ L.min^{-1}=3.4\ m^3.min^{-1}$

∵Density of water is 1 kg per liter

∴mass flow rate of water, $\dot{m}=3400\ kg.min^{-1}$

height of pumping, $h=75\ m$

efficiency of motor drive, $\eta=0.9$

diameter of pipe, $D =0.2\ m$

Now the power required for pumping the water at given conditions:

$P=\dot{m}.g.h$

$P=\frac{3400}{60} \times 9.8\times 75$

$P=41650\ W$

Hence the electric power required:

$P_E \times \eta=P$

$P_E \times 0.9=41650$

$P_E=46.2778\ kW$

Flow velocity is given as:

$v=\dot{V}\div a$

where: a = cross sectional area of flow through the pipe

$v=\frac{3.4}{60}\div (\pi.\frac{0.2^2}{4} )$

$v=1.804\ m.s^{-1}$

3 0

2 years ago