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2 years ago

Help anyone can help me do this question,I will mark brainlest.

Mathematics

1 answer:

astraxan [27]2 years ago

8 0

d =√((x_2-x_1)²+(y_2-y_1)²)

This is the formula of distance between

So, I hope u will get all answer of the questions by using this formula...

Thanks...

You might be interested in

The first term in the sequence is 1, and each other term is 5 more than three times the previous term.

marin [14]

$a_1=1, a_n=a_{n-1}+5$ ( $n>1$ ).

Hope this helps.

6 0

2 years ago

Solve this system of equations

olga_2 [115]

Answer:

D) x = 4, y = -2, z = 3

Step-by-step explanation:

x = 3z − 5

2x + 2z = y + 16

2(3z - 5) + 2z = y + 16

6z - 10 + 2z = y + 16

8z = y + 26 ---> (A)

7x − 5z = 3y + 19

7(3z - 5) - 5z = 3y + 19

21z - 35 - 5z = 3y + 19

16z = 3y + 54 ---> (B)

8z = y + 26

16z = 3y + 54

2(y + 26) = 3y + 54

2y + 52 = 3y + 54

y = -2

8z = -2 + 26

8z = 24

z = 3

x = 3(3) - 5

x = 4

8 0

2 years ago

The distance from the school to Brandi's house is 1,240 meters. Leaving the school, she rides her bicycle for 60 seconds at a sp

Alina [70]

14,880 seconds i think

4 0

2 years ago

Jane and Sali cycled along the same 63km route. Jane took 3.5 hours to cycle the 63km.

Arisa [49]

Answer:

sali's speed was 18.75 km/h

Step-by-step explanation:

Jane took 3.5 hours to cycle the 63 km.

As, , so the speed of Jane will be:

Suppose, the speed of Sali is km/h

Sali caught up with Jane when they had both cycled 30 km.

So, the time required for Jane to cycle 30 km and the time required for Sali to cycle 30 km

Given that, Sali started to cycle 4 minutes or after Jane started to cycle. So, the equation will be.......

5 0

2 years ago

Eddi Din [679]

Answer: The relative frequency of column A in group 1= $0.75$

The relative frequency of column B in group 1= $0.25$

The relative frequency of column A in group 2= $0.56$

The relative frequency of column B in group 2= $0.44$

Step-by-step explanation:

The relative frequency is the ration of each frequency by the total value in particular group.

For group 1 : Total =102+34=136

The relative frequency of column A in group 1= $\frac{102}{136}=0.75$

The relative frequency of column B in group 1= $\frac{34}{136}=0.25$

For group 2 : Total =18+14=32

The relative frequency of column A in group 2= $\frac{18}{32}=0.5625\approx0.56$

The relative frequency of column B in group 2= $\frac{18}{32}=0.4375\approx0.44$

7 0

2 years ago

Help anyone can help me do this question,I will mark brainlest.​

Help anyone can help me do this question,I will mark brainlest.