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2 years ago

Using the numbers 2,7,13,11,5 can you get the total of 23? (No negatives, No repetitive Numbers and only)

Mathematics

1 answer:

choli [55]2 years ago

3 0

Answer:

7, 11, 5

Step-by-step explanation:

7 + 11 = 18

18 + 5 = 23

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Deshaun took 2 5/8 hours to clean the bathroom. Then took 1/4 hours to clean the den . How much total time did deshaun take to c

natulia [17]

Answer:

2.875 hours 2 5/8 plus 1/4 equals 2.875

7 0

2 years ago

Can u find a it please

blsea [12.9K]

Answer:

3 + 3 + 1

Step-by-step explanation:

The doubles is 3+3 which is 6 plus 1 is 7

6 0

2 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

2 years ago

Eric tossed two coins in the air at the same time. He recorded the results of each toss. He tossed the coins 100 times. About ho

Anna007 [38]

Answer:

25 times

Step-by-step explanation:

p(HT) p(hh) p(tt) p(HT)

h-heads

t-tails

p(hh)=(1/4*100)

6 0

2 years ago

Evaluate: <img src="https://tex.z-dn.net/?f=%5Csqrt%5B-3%5D%7B27%7D" id="TexFormula1" title="\sqrt[-3]{27}" alt="\sqrt[-3]{27}"

GenaCL600 [577]

Answer:

1/3 is the simplified form for given expression.

Step-by-step explanation:

Given that:

= $\sqrt[-3]{27}$

By simplifying:

Radical sign will be removed as follows:

= $27^{-1/3}$

For removing the "-" sign from power, base will be inverted:

= $(1/27) ^ {1/3}$

27 can also be written as 3 * 3 * 3 = 3^3

So,

= $(1/3^3)^{1/3}$

= $1^{1/3} / 3^{3* 1/3}$

By simplifying we get:

= 1/3

i hope it will help you!

6 0

2 years ago