Y = -1 is a horizontal line going through "-1" on the y axis
Note that the point (1,2) is exactly 3 units of distance above the line y = -1
When we reflect across this line, the point (1,2) will just move straight down to exactly 3 units of space below the line y = -1. Since we are not shifting left or right, the x coordinate of our original point will not change. The y coordinate of our original point will now need to be reduced by 6(3 units down to get to the line of reflection and then 3 more down to get to the image location)
The coordinates of the image point will be (1, -4)
Now we need to do the same process with (1, -4) being reflected across y=1
Note (1,-4) is 5 units of distance below the line y = 1 , so we need to reflect the point upward so that the image point is located exactly 5 units of distance above the line y = 1 Again, the x coordinate does not change, and our final image coordinates are (1, 6)
I guess more simply stated, if you're just looking for the number in the green box it would be " 1 " .. Reflecting points across horizontal lines only result in changes of the "y" coordinate since there is no shift left or right.
Answer: Most likely 13cm
Step-by-step explanation: <em>because it’s between 10cm and 16cm and thes no picture and set of choices so I hope this right.</em>
Answer:
Use the given slope and point to substitute into the point-slope formula y−y1=m(x−x1).
Slope-intercept form:
y=3x²+4x−25
Point-slope form:
y+5=(3x+10)⋅(x−2)
Step-by-step explanation:
Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"
Answer:
7n + 9 = n² + 1
n = -1, 8
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Factoring
- Solving quadratics
Step-by-step explanation:
<u>Step 1: Set up Equation</u>
"Nine more" is + 9
"Seven times a number" is 7n
"One more" is + 1
"Square of the [same] number" is n²
7n + 9 = n² + 1
<u>Step 2: Solve for </u><em><u>n</u></em>
- Subtract 7n on both sides: 9 = n² - 7n + 1
- Subtract 9 on both sides: 0 = n² - 7n - 8
- Factor quadratic: 0 = (n - 8)(n + 1)
- Solve roots: n = -1, 8
