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2 years ago

7

By increasing the list price of a book by ₹10 a person can buy a 10 books less for ₹1200 Find the original list price of the boo

k. ( form Quadratic equation for the question)

1 answer:

Anarel [89]2 years ago

6 0

Answer:

cwbmwl2h2h2jl2bcek2k3cgwkel

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A bouqet had 10 flower and sold it for 90$ which is the rate of $_ per flower

lana [24]

Answer:

$9 per flower

Step-by-step explanation:

divide cost ($90) by the number of items (10 flowers)

6 0

2 years ago

Read 2 more answers

Mr. Hynes buys a large variety bag of Hershey chocolates to give out for Valentine’s Day. The bag of chocolates costs $8.00 and

Tema [17]

I think the answer is 8$ but i an not sure

7 0

2 years ago

Solve the inequality for x: -3(2x+5) < -45

balandron [24]

Answer:

x>5

Step-by-step explanation:

-3(2x+5)<-45

2x+5<-45/-3

2x+5<15

2x<15-5

2x<10

x<10/2

x<5

x>5

7 0

2 years ago

The product of 5 and a number n is at least 25

Crazy boy [7]

5n≥25
and if you divide 5 on both sides, n≥5 (I don't know if you are supposed to solve or simply put it in the equation form).

Product refers to multiplication. so 5 and n are being multiplied in the equation.
However, instead of using an equal sign, the sign for "greater than or equal to" must be used. "At least" is a term equivalent to "greater than or equal to".

4 0

2 years ago

A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph

belka [17]

Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

P(Smoker) =

$P(S) = \dfrac{340}{2000}=0.17$

P(emphysema) =

$P(E) = \dfrac{25}{2000}= 0.0125$

P(Smoker and emphysema) =

$P(S\cap E) = \dfrac{21}{2000} = 0.0105$

Two events A and B are said to be independent if

$P(A\cap B)=P(A)\times P(B)$

Checking conditions for independence:

$P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)$

Thus, the events being a heavy smoker and having emphysema are not independent.

3 0

2 years ago