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2 years ago

Suppose the linear regression line y = 4.009x - 77.531 predicts a pizza

Mathematics

1 answer:

fredd [130]2 years ago

7 0

Answer:

Option C, 1225

Step-by-step explanation:

y=4.009x-77.531

selling 325 pizzas, so x=325, now putting the value of x in the equation,

y=4.009×325-77.531

or, y=1225.394

y = 1225.394, which is the profit, if we approximate it to the nearest value, it's $1225

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Work out the surface area of the shapes in the attached file

grin007 [14]

Answer:

Find the area of every shape

12 x 9 = 108. Don't divide because there is two

12 x 14 = 168

14 x 9 = 126

15 x 14 = 210

108 + 168 + 126 + 210 = 612

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2 x pi x radius x height + 2 x radius x radius x height

466.5

Step-by-step explanation:

6 0

2 years ago

Tyrel evaluated the expression 2 1/2−3/4. Which is one way he can check his work?

Oxana [17]

Answer:

1 3/4 = 7/4 = 1.75

Step-by-step explanation:

The process to arrive to the solution is explained in the pictures below.

Tyler needed to convert the mixed fraction

2 1/2 = (4+1)/2 = 5/2

If we multiply by 2 numerator and denominator

5*2/2*2 = 10/4

We substract

10/4 - 3/4 = 7/4 = 1.75

3 0

2 years ago

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

1 year ago

Which equation shows the relationship between x & y?

algol13

I believe it is the first one but I might be wrong.

3 0

2 years ago

HELP!

olchik [2.2K]

C.35cm
Should be the right answer

5 0

2 years ago