6x^2 - 2x + 1 is a quadratic formula from the form ax^2 + bx + c. This form of equation represents a parabola.
Finding 6x^2 - 2x + 1 = 0, means that you need to find the zeroes of the equation.
Δ = b^2 - 4ac
If Δ>0, the equation admits 2 zeroes and 6x^2 - 2x + 1 = 0 exists for 2 values of x.
If Δ<0, the equation doesn't admit any zero, and 6x^2 - 2x + 1 = 0 doesn't exist since the parabola doesn't intersect with the axe X'X
If Δ=0, the equation admits 1 zero, which means that the peak of the parabola is touching the axe X'X.
In 6x^2 - 2x + 1, a=6, b=-2, and c =1.
Δ= b^2 - 4ac
Δ=(-2)^2 - 4(6)(1)
Δ= 4 - 24
Δ= -20
Δ<0 so the parabola doesn't intersect with the Axe X'X, which means there's no solution for 6x^2 - 2x + 1 = 0.
I've added a picture of the parabola represented by this equation under the answer.
Hope this Helps! :)
Here is the answer to the question. Vertical asymptotes a<span>re vertical lines which correspond to the zeroes of the denominator of a </span>rational function. Therefore, in order to find the vertical asymptote of a rational expression, what you are going to do is to <span>set the denominator equal to 0 and solve for x. Hope this helps.</span>
Answer:
26 degrees below zero
Step-by-step explanation:
add the two numbers together and since 12 below zero would be -12 and it drops 14 more it would be -12 - 14 which would lead to -26 because since both are negative its basically adding then putting the negative sign in front.
The figures on the top left and the bottom right have rotational symmetry.
Rational) No
Integer) No
Whole) Yes
Natural) Yes
Describe the number:
It’s whole and Natural and it is 5