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2 years ago

How many of hours of work is normal for a shift?

Mathematics

2 answers:

saw5 [17]2 years ago

8 0

Like an 8, a 9-5 is what most people have so over 40 hours is overtime

Ira Lisetskai [31]2 years ago

3 0

Answer: 7-9

Step-by-step explanation: normal job hours

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the two guy wires supporting a tower form an isosceles triangle with the ground. each of the base angles of the triangle is 4 ti

user100 [1]

Internal measure of a triangle is 180 degrees
base angles of an isosceles triangle are =
therefore each base angle is 4x
4x+4x+x=180
9x= 180
x=20
vertex angle= 20

3 0

2 years ago

Sandra needs 6 pieces of rope, each measuring 8 inches in length. She is going to cut the 6 pieces from a rope that is 84 inches

soldier1979 [14.2K]

36 inches of rope will be left because 6*8 is 48 and you subtract 48 from 84 to get 36.

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2 years ago

What is the scale factor from ABC to XYZ? A 1/5 B 1/6 C 5 D 6

nadya68 [22]

The scale factor is 6

4 0

2 years ago

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6) 2(n + 5) = -2 help i wasn’t paying attention in my google meet

bonufazy [111]

Answer: the answer is -6

2(n+5) = -2

2n + 10 = -2

2n = -2 - 10

2n = -12

2n *1/2 = -12 * 1/2 = -6

n = -6

5 0

2 years ago

Read 2 more answers

In the circle below, DB = 22 cm, and m<DBC = 60°. Find BC. Ignore my handwriting.

Karo-lina-s [1.5K]

Answer:

$BC=11\ cm$

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

$m\angle DBC=\frac{1}{2}[arc\ DC]$

substitute the values

$60\°=\frac{1}{2}[arc\ DC]$

$120\°=arc\ DC$

$arc\ DC=120\°$

step 2

Find the measure of arc BC

we know that

$arc\ DC+arc\ BC=180\°$ ----> because the diameter BD divide the circle into two equal parts

$120\°+arc\ BC=180\°$

$arc\ BC=180\°-120\°=60\°$

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

$m\angle BDC=\frac{1}{2}[arc\ BC]$

substitute the values

$m\angle BDC=\frac{1}{2}[60\°]$

$m\angle BDC=30\°$

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

$sin(\angle BDC)=BC/BD$

$BC=(BD)sin(\angle BDC)$

substitute the values

$BC=(22)sin(30\°)=11\ cm$

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2 years ago