F would be 1. G would be 4. E would be negative 3
8171 9 inches and different radius
Answer:
Step-by-step explanation:
Because midpoints were used to make similar triangles we can say
AC=2(DE)
5x+12=2(9x-20)
5x+12=18x-40
-13x+12=-40
-13x=-52
x=4
AC=5x+12
AC=5(4)+12
AC=20+12
AC=32
Answer:
A
Step-by-step explanation:
If we insert the original coordinates into the problem, we will find the answer.
(2+2, 1-5)
so, once solved
(4, -4)
remember, adding to X means moving the point right, subtracting to X means moving left.
Adding to Y means moving the point up, subtracting to Y means moving down.
Given that a unshaded rectangle is inscribed in a shaded circle, the area of the shaded region is 72.67m².
Given that a unshaded rectangle is inscribed in a shaded circle.
- Diameter of the circle d = 13m
- Radius r = d/2 = 13m/2 = 6.5m
- Dimension of length of the rectangle l = 12m
- Dimension of width of the rectangle w = 5m
- Area of the shaded region As = ?
First we calculate the area of the shaded circle.
A = πr² = π × ( 6.5m )²
A = 132.665m²
Area of the shaded circle is 132.665m².
Area of the unshaded rectangle will be;
A = l × w
A = 12m × 5m
A = 60m²
Area of the unshaded rectangle is 60m².
Now, area of the shaded region will be;
= Area of the shaded circle - Area of the unshaded rectangle
= 132.665m² - 60m²
= 132.665m² - 60m²
= 72.67m²
Given that a unshaded rectangle is inscribed in a shaded circle, the area of the shaded region is 72.67m².
Learn more about area polygons here: brainly.com/question/22590672
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