Velocity may be positive,negative or zero.Explain this statement with diagram.

how much does a bookshelf weigh if the movers are pushing it at a speed of 10 m/s^2 by applying 100 N force

Delicious77 [7]

Answer:

10 kg

Explanation:

Assuming a frictionless surface, then force F=ma where F is the applied force, m is the mass and a is acceleration. Making m the subject of the formula then $m=\frac {F}{a}$

Substituting 100 N for the applied force F and 10 m/s^2 for acceleration a then the value of m will be $m=\frac {100}{10}=10\ kgs$

Therefore, in terms of kilograms, the bookshelf weighs 10 Kg

7 0

2 years ago

Which of these statements correctly describe the atom? Check all that apply. All matter on Earth is made up of atoms. The subato

Irina18 [472]

True: All matter on earth is made up of atoms.

False: Subatomic particles don't identify an element. I give you an electron. Can you tell me where it came from?

False: (1/2) A neutron has no charge [That's the True part]. It identifies the element. (Not true).

True: description of an electron.

True: description of a proton

3 0

2 years ago

Read 3 more answers

A-10A twin-jet close-support airplane is approximately rectangular with a wingspan (the length perpendicular to the flow directi

Sidana [21]

Solution :

Given :

Rectangular wingspan

Length,L = 17.5 m

Chord, c = 3 m

Free stream velocity of flow, $V_{\infty}$ = 200 m/s

Given that the flow is laminar.

$Re_L=\frac{\rho V L}{\mu _{\infty}}$

$=\frac{1.225 \times 200 \times 3}{1.789 \times 10^{-5}}$

$= 4.10 \times 10^7$

So boundary layer thickness,

$\delta_{L} = \frac{5.2 L}{\sqrt{Re_L}}$

$\delta_{L} = \frac{5.2 \times 3}{\sqrt{4.1 \times 10^7}}$

= 0.0024 m

The dynamic pressure, $q_{\infty} =\frac{1}{2} \rho V^2_{\infty}$

$=\frac{1}{2} \times 1.225 \times 200^2$

$=2.45 \times 10^4 \ N/m^2$

The skin friction drag co-efficient is given by

$C_f = \frac{1.328}{\sqrt{Re_L}}$

$=\frac{1.328}{\sqrt{4.1 \times 10^7}}$

= 0.00021

$D_{skinfriction} = \frac{1}{2} \rho V^2_{\infty}S C_f$

$=\frac{1}{2} \times 1.225 \times 200^2 \times 17.5 \times 3 \times 0.00021$

= 270 N

Therefore the net drag = 270 x 2

= 540 N

7 0

2 years ago

A car begins at rest (0 velocity), 5 seconds later it is travelling at 20 meters/per second. What was the acceleration of the ve

klasskru [66]

use the formula

v= u+ at

v is final velocity , u is initial velocity , a is acceleration and t is time

put the values

20 = 0+ a×5

a = 4 m/s²

4 0

1 year ago

Read 2 more answers

A man attempts to pick up his suitcase of weight ws by pulling straight up on the handle. (See Figure 1) However, he is unable t

cupoosta [38]

Answer:

Normal force, $N = W_s - F$

Explanation:

Let $w_s$ is the weight of suitcase. A man attempts to pick up his suitcase by pulling straight up on the handle. The weight of the suitcase in downward direction. The normal force is acting in upward direction. Let F is the force with which it is pulled straight up.

So, the normal force is given by :

$N = W_s - F$

N = mg - F

mg is the weight of the suitcase.

Hence, this is the required solution.

3 0

2 years ago

Velocity may be positive,negative or zero.Explain this statement with diagram.​

Velocity may be positive,negative or zero.Explain this statement with diagram.