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1 year ago

Kepler's laws, satellites motion and weightlessness

Physics

1 answer:

Anon25 [30]1 year ago

3 0

Answer:

First Kepler law states that Each planet describes an ellipsoidal motion about the sun as its single focus.

Second Kepler law states that An imaginary line joining a planet to the Sun sweeps out equal areas in equal time intervals.

Third Kepler law states that The squares of period of revolution of the planet around the sun are proportional to the cubes of mean distance between the planet and the sun.

Weightlessness is the condition where the body has zero gravity ( its acceleration is equal to the acceleration due to gravity )

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A 0.2-kg ball moving at 2.0 m/s perpendicular to a wall rebounds from the wall at 1.5 m/s. The impulse given to the ball is:

kiruha [24]

Answer:

J = 0.7 N-s away from wall

Explanation:

Given that,

Mass of the ball, m = 0.2 kg

Initial speed of the ball, u = 2 m/s

Final speed of the ball, v = -1.5 m/s (as it rebounds)

Impulse is equal to the change in momentum. So,

$J=m(v-u)\\\\J=0.2\times (-1.5-2)\\\\J=-0.7\ N-m$

So, the impulse given to the ball is 0.7 N-m and it is away from the wall. Hence, the correct option is (c).

8 0

2 years ago

a trampoline launches a 50kg person 2m into the air. if the springs push with 1960N of force, how much displacement was there in

Lina20 [59]

Answer: 0.5 m

Explanation:

Given

Mass of the person is $m=50\ kg$

Trampoline launches the person into the air up to height of $h=2\ m$

Force experience by springs is $F=1960\ N$

Here, the work done on displacing the springs is equivalent to the Potential energy acquired by the person i.e.

$\Rightarrow F\cdot x=mgh\quad [\text{x=displacement of the trampoline}]\\\\\text{Insert the values}\\\\\Rightarrow x=\dfrac{50\times 9.8\times 2}{1960}\\\\\Rightarrow x=\dfrac{980}{1960}\\\\\Rightarrow x=0.5\ m$

6 0

2 years ago

Read 2 more answers

What is the force of a ball if it has a mass of 10 kg and accelerates at an acceleration of 20 m/s^2? *

vampirchik [111]

Answer:

200N

Explanation:

mass(m) = 10 kg

acceleration(a) = 20 m/s^2

Force = mass * acceleration

= 10*20

= 200 N

Force = 200N

4 0

1 year ago

A bullet fired vertically at a velocity of 36m/s .after 45 the bullet hit the top of a bulid how height is a bulid?

zzz [600]

Answer:

The height of the building is 8,302.5 m

Explanation:

Given;

velocity of the projectile, u = 36 m/s

time of motion, t = 45 s

Let the upward direction of the bullet be negative,

The height of the building is calculated as;

$h = ut - \frac{1}{2} gt^2\\\\h = (36\times 45) - (\frac{1}{2} \times 9.8 \times 45^2)\\\\h = 1620 - 9922.5\\\\h = -8,302.5 \ m\\\\The \ height \ of \ the \ building \ is \ 8,302.5 \ m$