solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
Answer:
-64
Step-by-step explanation:
a(b - c)
a = -8
b = 12
c = 4
So, you'd plug in those numbers:
-8(12 - 4)
You'd start within the parenthesis's, so:
(12 - 4), which equals (8)
-8(8)
= -64
Answer:
2,-4
-2,-3
_____
1
Step-by-step explanation:
That is how write the equation because you have to line them up by the higher x or y value
A. Is changed or manipulated in the experiment