Mass of aluminum = (1.50 m^3)( 2.70 x 10^3 kg/m^3) = 4050 kg
The intention of density is the assembly per volume of the substance. This is an intrinsic property consequently the size (or any external feature) does not change this effects.
<h3>What is Aluminum?</h3>
- Aluminum is a silvery-white metal, the 13 elements in the regular table. One surprising fact regarding aluminum is that it's the most widespread metal on Earth, making up more than 8% of the Earth's core mass. It's also the third most standard chemical essence on our planet after oxygen and silicon.
- The formed aluminum is in everyday use in mining, manufacturing, and trade in the United States; the formed aluminum is used with reasonable uniformity in Great Britain and typically by chemists in the United States.
- Aluminum (Al), also spelled aluminum, chemical component, a weightless silvery-white metal of main Group 13 (IIIa, or boron group) of the periodic table. Aluminum is the most plentiful metallic component in Earth's crust and the numerous widely used nonferrous metal.
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I would think that b would be the right answer
Answer:
Endothermic hope that helps
Explanation:
Answer:
ΔH°rxn = - 433.1 KJ/mol
Explanation:
- CH4(g) + 4Cl2(g) → CCl4(g) + 4HCl(g)
⇒ ΔH°rxn = 4ΔH°HCl(g) + ΔH°CCl4(g) - 4ΔH°Cl2(g) - ΔH°CH4(g)
∴ ΔH°Cl2(g) = 0 KJ/mol.....pure element in its reference state
∴ ΔH°CCl4(g) = - 138.7 KJ/mol
∴ ΔH°HCl(g) = - 92.3 KJ/mol
∴ ΔH°CH4(g) = - 74.8 KJ/mol
⇒ ΔH°rxn = 4(- 92.3 KJ/mol) + (- 138.7 KJ/mol) - 4(0 KJ/mol) - (- 74.8 KJ/mol)
⇒ ΔH°rxn = - 369.2 KJ/mol - 138.7 KJ/mol - 0 KJ/mol + 74.8 KJ/mol
⇒ ΔH°rxn = - 433.1 KJ/mol
Answer:
Cr (HSO4)3
Explanation:
its molecular weight is 343.20 g/mol
its molecular formula can also be written as CrH3O12S3
molar mass of Cr (HSO4)3 can be calculated by following method;
atomic mass of Cr = 51.9961 u
atomic mass of H = 1 u
atomic mass of S = 32.065 u
atomic mass of O = 16 u
molar mass of Cr(HSO4)3 = 51.9961+ 1.00784×3 + 32.065×3 + 15.999×12
molar mass of Cr(HSO4)3 =51.9961+3.02352+96.195+ 191.988
molar mass of Cr(HSO4)3 = 343.20 g/mol