Answer:
Current: 1.0 Amperes
The minimum current is flowing through path D
Explanation:
We first find the equivalent resistance to the three resistors in parallel ( which is the total resistance of the circuit) via the equation:
with this info, we can estimate the current going through branch A using Ohm's Law, and the information that the power source is 6 V:
where the current comes in units of Amperes since all other the quantities are given in the SI system, and we can round this answer to 1.0 Amp following the request to round it to the tenth.
The current will be the lowest through the branch with the largest resistor due to the fact that less current will flow through the path of more resistance.
Than means that the lowest current will be registered through branch D where the 50 resistor is.
The wavelength of light is
given as 463 nm or can also be written as 463 x 10^-9 m. [wavelength = ʎ]
We know that the speed of
light is 299 792 458 m / s or approximately 3 x 10^8 m / s. [speed of
light = c]
Given the two values, we can calculate
for the frequence (f) using the formula:
f = c / ʎ
Substituting the given
values:
f = (3 x 10^8 m / s) / 463 x
10^-9 m
f = 6.48 x 10^14 / s = 6.48 x
10^14 s^-1
<span>f = 6.48 x 10^14 Hz</span>
Answer:
option (c)
Explanation:
When an object thrown upwards, the value of acceleration acting on the object is acceleration due to gravity which is always acting towards the earth.
As it falls downwards, the acceleration is again equal to the acceleration due to gravity.
So, the ball's acceleration is constant.
If a car increases its speed from 20km/h to 100 km/h undergoes positive acceleration. Hope this helped!
Answer:
-35 m/s
Explanation:
Momentum is conserved.
Momentum before firing = momentum after firing
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Before the bullet is fired, the bullet and rifle have no velocity, so u₁ and u₂ are 0.
0 = m₁v₁ + m₂v₂
Given m₁ = 0.7 kg, v₁ = 350 m/s, and m₂ = 7 kg:
0 = (0.7 kg) (350 m/s) + (7 kg) v
v = -35 m/s
The rifle recoils at 35 m/s in the opposite direction.