Let, the integers = x,(x+1)
x*(x+1) = 56
x²+x = 56
x²+x-56 = 0
x²+8x-7x-56=0
x(x+8)-7(x+8)=0
x+8= 0 OR x-7=0
x = -8 OR x = 7
it would be -8 & -7 or 7 & 8
Answer:
The answer is: always
Step-by-step explanation:
All numbers even irrational numbers are real numbers.
Hope it helps!
Answer:
x = 2
y = 1
Step-by-step explanation:
3x - y = 5..............(1)× 1
2x + y = 5...….......(2)× 1
3x - y = 5..............(3)
2x + y = 5.............(4)
Cancel y
3x + 2x = 5 + 5
5x = 10
Divide both sides by 5
x = 2
Substitute for the value of y
3x - y = 5
3(2) - y = 5
6 - y = 5
6 - 5 = y
1 = y
y = 1
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You can use (a+b)2 = a2+2ab+b2.
(2x - 3)2 = (2x)2 + 2(2x)(-3) + (-3)2 = 4x2 - 12x + 9
Or you can use FOIL.
(2x - 3)2 = (2x - 3)(2x - 3) = (2x)2 + (2x)(-3) + (-3)(2x) + (-3)2 = 4x2 - 12x + 9
hope I could be helpful