<h3>The <u>
complete question</u>
would be:</h3>
In a common laboratory experiment in general chemistry, students are asked to determine the relative amounts of benzoic acid and charcoal in a solid mixture. Benzoic acid is relatively soluble in hot water, but charcoal is not. Devise a method for separating the two components in the mixture.
<h3>The <u>
solution</u> for that would be:</h3>
First you put the mixture in hot water and allow the benzoic acid to separate. Next funnel it and then see what's on the funnel paper. Lastly, heat the leftover water and see what's left after it evaporates.
<h3><u>What are laboratory experiments ?</u></h3>
- Using controlled surroundings to test theories, researchers may develop laboratory experiments.
- Laboratories are rooms or specially constructed facilities within buildings that are often found on college and university campuses and are utilized for academic research.
- It's crucial to differentiate between experiments and other kinds of research investigations carried out in lab settings.
- Even if a research study takes place in a lab, it is not always an experiment.
- In order to evaluate causal conclusions regarding the links between independent and dependent variables, laboratory studies, like all genuine experimental designs, use procedures of random assignment of participants and control groups.
To view more about experiments, refer to:
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Phosphorous has 5 valence electrons and so gaining 3 electrons will make it isoelectronic with the stable noble gas argon, and will produce the P3- ion
Answer and explanation:
The attached figure shows five different structures for the chemical formula C4H5O5, but only one of these structures represent the malic acid.
Malic acid is a dicarboxylic acid, this means malic acid has two
-COOH groups. Also, malic acid is a secundary alcohol, which means it has a R2-C-OH group.
-Structure A has two carboxylic groups, but it doesn´t have a secundary alcohol.
-Structure B doesn´t have any caborxylic group.
-Structure C has two carboxylic groups and it is a secundary alcohol. Structure C is the Malic acid
Answer: The boiling point of a sample of Propanone at 180 kPa is 75 C. The correct answer is 2.
Explanation:
Propanone is more commonly known under the name "acetone." The boiling point of this compound at 180 kPa will be 75 C. It is an organic compound and its formula is (CH3)2CO.
This compound does not any color, it is highly flammable, and volatile. This compound does have a distinguished odor. It is used in labs, in industry settings, and in the home for various things. The human body does produce this compound naturally and the body disposes of this compound.