Given:
Current revenue = $6000
<span>R(f)= -100f^2 + 400f + 6000
where f is a whole number of $5 fee increases
We are told to find f, when R(f) </span><span>< 6000
Since </span>R(f)= -100f^2+400f+6000
R(f) < 6000 ⇒ -100f^2+400f+6000 < 6000
Subtract 6000 from both sides
-100f^2 + 400f + 6000 - 6000 < 6000 - 6000
-100f^2 + 400f < 0
⇒ 400f - 100f^2 < 0
Divide the equation by 100
400f/100 - 100f^2/100 < 0/100
4f - f^2 < 0
Add f^2 to both sides of the equation
4f - f^2 + f^2 < 0 + f^2
4f < f^2
Divide both sides by f
4f/f < (f^2)/f
4 < f
⇒ f > 4
⇒ f ≥ 5
Therefore, <span> for 5 or more numbers of $5 fee increases, the revenue from fees will actually be less than its current value.</span>
In 1 second it beats about 53 times
In 5 seconds it will beat about (53/1*5) times
= 265 times
We want to find a fraction that is between
There are several ways to go about this.
There are also infinitely many fractions that can be found between the given fractions.
Let us go for the one in the middle of the two fractions.
So we add the two fractions and divide by 2.
a)
Find LCM for the numerator
Simplify:
b)
c)
d)
To simplify the expression given <span>sinx+cosx/sinxcosx, the first step to do is to divide each term of the numerator to the denominator. In this case, the resulting expression is 1/cos x + 1/ sin x. These terms are inverse trigonometric identities. The answer is sec x + csc x. </span>
Answer:
8 2/3 divided by 4 1/8=2 1/10 is Correct
exactly 2 10/99